Dear Students, if-elif-else python exercises Class11 provides you the practical list of python programs for annual exam practical records.

## if-elif-else python exercises Class11

[1] The given number is odd or even.```
def odd_even():
n = int(input("Enter any number:"))
if n % 2!=0:
print("No is odd")
else:
print("No is even")
odd_even()
```

[2] The given number is positive or negative or zero.
```
def pnz_check():
n = int(input("Enter any number:"))
if n>0:
print("No is positive")
elif n<0:
print("No is negative")
else:
print("Zero")
pnz_check()
```

[3] The given number is of one digited or two digited or three digited or more than three digited.
```
def dig_check():
n = int(input("Enter any number:"))
if n>0 and n<10:
print("One digit number")
elif n>10 and n<100:
print("Two digit number")
elif n>100 and n<1000:
print("Three digit number")
else:
print("More than three digit number")
dig_check()
```

[4] The entered number is smallest 4 digit number or not.
```
def smallest4digit():
n = int(input("Enter any number:"))
if n==1000:
print("n is smallest 4 digit no")
else:
print("n is not a smallest 4 digit no")
smallest4digit()
```

[5] The given character is an uppercase letter or lowercase letter or a digit or a special character.
```
def check_chr():
ch = input("Enter a character to check:")
if ord(ch)>=65 and ord(ch)<=90:
print("The character", ch, " is an uppercase letter")
elif ord(ch)>=97 and ord(ch)<=122:
print("The character", ch, " is a lowercase letter")
elif ord(ch)>=48 and ord(ch)<=57:
print("The character", ch, " is a digit")
else:
print("The character", ch, " is a special chacracter")
check_chr()
```

[6] The given year is a leap year or not.```
def check_leapyear():
year = int(input("Enter a character to check:"))
if (year%4==0 and year%100!=0) or (year%400==0):
print("Year is a leap year")
else:
print("Year is not a leap year")
check_leapyear()
```

[7] The given number is divisible by 5 or not.
```
def check_div5():
n = int(input("Enter a number to check:"))
if n%5==0:
print("No is divisible by 5")
else:
print("No is not divisible by 5")
check_div5()
```

[8] Find maximum number out of given three numbers.```
def check_max3():
n1,n2,n3 = int(input("Enter no1:")),int(input("Enter no2:")),int(input("Enter no3:"))
if n1>n2 and n1>n3:
print("No1 is maximum")
elif n2>n1 and n2>n3:
print("No2 is maximum")
elif n3>n1 and n3>n2:
print("No3 is maximum")
else:
print("All are equal")
check_max3()
```

[9] Find minimum number out of given three numbers.
**Do it yourself.**

Watch this video lesson explains the programms.

[10] Write a program that reads three positive numbers a, b, c and determines whether they can form the three sides of a triangle.```
def check_3tri():
a=int(input("Enter no1:"))
b=int(input("Enter no2:"))
c=int(input("Enter no3:"))
if(((a+b)<=c)or((b+c)<=a)or((c+a)<=b)):
print("It can not form the triangle")
else:
print("It can form the triangle")
check_3tri()
```

[11] Whether the triangle will be an obtuse-angle, or a right-angle or an acute-angle triangle. ```
def check_tritype():
a=int(input("Enter no1:"))
b=int(input("Enter no2:"))
c=int(input("Enter no3:"))
square_a = a**2
square_b = b**2
square_c = c**2
if square_a == square_a + square_b or square_b == square_a + square_c or square_c == square_a + square_b:
print("Right-angled Triangle")
elif square_a > square_c + square_b or square_b > square_a + square_c or square_c > square_a + square_b:
print("Obtuse-angled Triangle")
else:
print("Acute-angled Triangle")
check_tritype()
```

[12] If the triangle is an acute angle triangle, determine further whether the triangle is equilateral, isosceles, or scalene.
```
def check_tritype2():
a=int(input("Enter no1:"))
b=int(input("Enter no2:"))
c=int(input("Enter no3:"))
if a==b==c:
print("Equilateral triangle")
elif a==b or b==c or c==a:
print("isosceles triangle")
else:
print("Scalene triangle")
check_tritype2()
```

[13] A toy vendor supplies three types of toys: Battery Based Toys, Key-based Toys, and Electrical Charging Based Toys. The vendor gives a discount of 10% on orders for battery-based toys if the order is for more than Rs. 1000. On orders of more than Rs. 100 for key-based toys, a discount of 5% is given, and a discount of 10% is given on orders for electrical charging based toys of value more than Rs. 500. Assume that the numeric codes 1,2 and 3 are used for battery based toys, key-based toys, and electrical charging based toys respectively. Write a program that reads the product code and the order amount and prints out the net amount that the customer is required to pay after the discount.
```
def compute_discount():
print("1. For Battery based Toys")
print("2. For Key based Toys")
print("3. Electric chargin based Toys")
opt = int(input("Enter the product code (1,2 or 3)?:"))
amt = int(input("Enter the amount:"))
if opt==1:
if amt>1000:
dis = amt * 0.1
else:
dis = 0
elif opt==2:
if amt>100:
dis = amt * 0.05
else:
dis=0
elif opt==3:
if amt>500:
dis = amt*0.1
else:
dis = 0
else:
print("Product is not available")
bill_amt= amt - dis
print("Customer has to pay:",bill_amt)
compute_discount()
```

[14] A function f is defined as follows :

f(x) = ax^{3} – bx^{2} + cx –d, if x > k

= 0, if x = k

= -ax^{3} + bx^{2} – cx +d, if x < k

Write a program that reads a, b, c, d, k and x and prints the value of f(x).

```
def sol14():
a = int(input("Enter a:"))
b = int(input("Enter b:"))
c = int(input("Enter c:"))
d = int(input("Enter d:"))
k = int(input("Enter k:"))
x = int(input("Enter x:"))
if x > k:
fx = a*(x**3) - b*(x**2) + c*x -d
if x ==k:
fx =0
if x < k:
fx = -a*(x**3) + b**x**2) - c*x + d
print(fx)
sol14()
```

[15] Write a program to do the following operations :

- Read any two positive integer numbers (say n1 & n2) and one character type operator (say opr). Note that opr is any mathematical operator.
- Depending upon the operator, do the appropriate operation. e. g. if opr is ‘+’ then the display the value obtained by evaluating the expression (n1 + n2).

```
def sol15():
n1 = int(input("Enter n1:"))
n2 = int(input("Enter n2:"))
print("+ for addition\n")
print("- for addition\n")
print("* for addition\n")
print("\ for division\n")
ch = input("Enter the choice:")
if ch=='+':
ans = n1 + n2
elif ch == '-':
ans = n1 - n2
elif ch == '*':
ans = n1 * n2
elif ch == '/':
ans = n1 / n2
else:
print("Invalid choice")
print("The answer is:",ans)
sol15()
```

**Below you will find the list of application based program list for if-elif-else python exercises Class11.**

Units Consumed | Charges |

0-100 | 0.50 per unit |

101-200 | Rs. 50 plus Rs. 1 per unit over 100 units |

201-300 | Rs. 150 plus 1.50 per unit over 200 units |

> 300 | Rs. 300 plus Rs.2 per unit over 300 units |

- Ask user to enter the Past meter reading and current meter reading.
- Find the units consumed.
- Compute the bill according to given matrix.

```
def sol16():
pmr = int(input("Enter past meter reading:"))
cmr = int(input("Enter current meter reading:"))
uc = cmr - pmr
if uc>0 and uc<=100:
bill_amt = uc * 0.50
elif uc>100 and uc<=200:
bill_amt = 50 + (uc-100) * 1
elif uc>200 and uc<=300:
bill_amt = 150 + (uc-200) * 1.50
else:
bill_amt = 300 + (uc-300) * 2
print("The bill amount is:",bill_amt)
sol16()
```

[17] A cloth showroom has announced the following discounts on the purchase of specific items :
Amount | Shorts | Pants | Shits/T-Shirts |

0-100 | – | 3% | 5% |

101-200 | 5% | 8% | 10% |

201-300 | 10% | 12% | 15% |

Above 300 | 18% | 20% | 22% |

- Ask user to enter the amount and assign following code for the items such as sh for shorts, p for pans and sht for shirts/t-shirts.
- Compute the discount and net amount paid by customer.

```
def sol17():
print("/'sh/' for Short")
print("/'p/' for Pants")
print("/'t/' for t-shirts")
opt = input("Enter the product code (/'sh/',/'p/',/'sht/')?:"))
amt = int(input("Enter the amount:"))
if opt=='s' opt=='S':
if amt>0 and amt<100:
dis = 0
elif amt>100 and amt<200:
dis = amt * 0.05
elif amt>201 and amt<300:
dis = amt * 0.1
else:
dis = amt * 0.18
elif opt=='p' opt=='P':
if amt>0 and amt<100:
dis = amt * 0.03
elif amt>100 and amt<200:
dis = amt * 0.08
elif amt>201 and amt<300:
dis = amt * 0.12
else:
dis = amt * 0.20
if opt=='t' opt=='T':
if amt>0 and amt<100:
dis = amt * 0.05
elif amt>100 and amt<200:
dis = amt * 0.10
elif amt>201 and amt<300:
dis = amt * 0.15
else:
dis = amt * 0.22
bill_amt = amt - dis
print("Customer has to pay:",bill_amt)
sol17()
```

[18] BSNL has three categories of customers: Industrial, Bulk Institutional and Domestic. The rates for these are tabulated below :
Category | Units | Rate |

Commercial | Minimum up to 5000 units | Rs. 1500 |

Next 5000 units | Rs. 0.25 per unit | |

Next 10000 units | Rs. 0.23 per unit | |

Above this | Rs. 0.20 per unit | |

Institutional | Minimum up to 5000 units | Rs. 1800 |

Next 5000 units | Rs. 0.30 per unit | |

Next 10000 units | Rs. 0.28 per unit | |

Above this | Rs. 0.25 per unit | |

Domestic | Minimum up to 100 Units | Rs. 75 |

Next 100 Units | Rs. 1.25 per unit | |

Next 200 Units | Rs. 2.00 per unit | |

Above this | Rs. 2.50 per unit |

- Ask user to enter customer category, Units.
- Compute the bill as per given criteria.
- Print bill in proper format.

```
def sol18():
cat = input("Enter the category(commerical, institutional, or domestic:")
units =int( input("Enter the units:"))
if cat == "commercial":
if units>0 and units<=5000:
bill = 1500
elif units>5000 and units<=10000:
bill = units * 0.25
elif units>10000 and units<=15000:
bill = units * 0.23
elif units>15000:
bill = units * 0.20
elif cat == "institutional":
if units>0 and units<=5000:
bill = 1800
elif units>5000 and units<=10000:
bill = units * 0.30
elif units>10000 and units<=15000:
bill = units * 0.28
elif units>15000:
bill = units * 0.25
if cat == "domestic":
if units>0 and units<=100:
bill = 75
elif units>100 and units<=200:
bill = units * 1.25
elif units>200and units<=300:
bill = units * 2
elif units>300:
bill = units * 2.50
print("*"*80)
print("The category:",cat)
print("Units:", units)
print("*"*80)
print("Bill amount:", bill)
sol18()
```

[19] A transport company charges the fare according to following table:
Distance | Charges |

1-50 | 8 Rs./Km |

51-100 | 10 Rs./Km |

> 100 | 12 Rs/Km |

Ask user to enter the distance and compute the fare.

```
def sol19():
distance = int(input("Enter distance:"))
if distance>=1 and distance<=50:
fare = distance * 8
elif distance>=51 and distance<=100:
fare = distance * 10
elif distance>100:
fare = distance * 12
else:
print("Invalid fare")
print("The total fare is:",fare)
sol19()
```

[20] The Sardar Patel Cricket Stadium, Motera has the following rates for different types of seats:
- Ordinary – 2500
- Pavillion – 3500
- Upper Pavillion – 4500
- Commentary Box – 6000
- VIP – 8000

They are giving 10% discount for online booking and 8% discount for advance booking and no discount is given for booking on match day from ticket window.

- Ask user to enter the booking type like online, advance or window booking.
- Ask user to select the types of seats.
- Compute the amount and print the ticket with proper format.

```
def sol20():
b_type = input("Enter booking type(online or advanced or window):")
s_type = input("Enter seat type(ordinary,pavallion,upper pavallion, commentary box,VIP):")
nop = int(input("Enter no. of persons:"))
if s_type=="ordinary":
rate = 2500
elif s_type=="pavallion":
rate = 3500
elif s_type=="upper pavallion":
rate = 4500
elif s_type=="commentary box":
rate = 6000
elif s_type=="VIP":
rate = 8000
else:
print("Invalid Seat Types")
amt = nop * rate
if b_type=="online":
dis_per = "10%"
dis = amt * 0.1
elif b_type=="advanced":
dis_per = "8%"
dis = amt * 0.08
elif b_type=="window":
dis_per = "0%"
dis = 0
net_amt = amt - dis
print("-"*120)
print("\t\t\tSardar Patel Cricket Stadium - Motera, Ahmedabad")
print("-"*120)
print("Your Seats:",s_type,"\t Booking type:",b_type)
print("No of seats:",nop,"\t Amount (before discount):", amt)
print("-"*120)
print("Discount in (%):",dis_per,"\t Discount amount:",dis)
print("Bill amount is", net_amt)
sol20()
```

Read notes for this concept from here.

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