In this article, I will provide Chapter 2 Encoding Scheme and Number System Class 11 NCERT Solutions. So let’s start1
Chapter 2 Encoding Scheme and Number System Class 11
Let’s start the solution of the encoding scheme and number system class 11 with basic questions.
- Write base values of binary, octal and hexadecimal number system.
- Binary – 2
- Octal – 8
- Hexadecimal – 16
- Give the full form of ASCII and ISCII.
- ASCII – Americal Standard Code for Information Interchange
- ISCII – Indian Script Code for Information Interchange
- Try the following conversions:
(IV) (49D)16=(?)10
4 | 9 | D |
2 | 1 | 0 |
4 x 162 | 9 x 161 | 13 x 160 |
4 x 256 | 9 x 16 | 13 x 1 |
1024 | 144 | 13 |
1181 |
(VI) (1010111)2 = (?)10
1 | 0 | 1 | 0 | 1 | 1 | 1 |
6 | 5 | 4 | 3 | 2 | 1 | 0 |
1 x 26 | 0 x 25 | 1 x 24 | 0 x 23 | 1 x 22 | 1 x 21 | 1 x 20 |
1 x 64 | 0 x 32 | 1 x 16 | 0 x 8 | 1 x 4 | 1 x 2 | 1 x 1 |
64 | 0 | 16 | 0 | 4 | 2 | 1 |
87 |
- Do the following conversions from decimal numbers to other number systems.
(ii)
(iv) (889)10 = (?)8
8 | 889 | 1 |
8 | 111 | 7 |
8 | 13 | 5 |
1 | 1 | |
Ans.: | 889 | 1571 |
(vi) (108)10 =(?)16
16 | 108 | 12-C |
6 | 6 | |
Ans.: | 108 | 6C |
Watch this video for more understanding:
5. Express the following octal numbers into their equivalent decimal numbers.
(i) 145
(ii) 6760
6 | 7 | 6 | 0 |
3 | 2 | 1 | 0 |
6 x 83 | 7 x 82 | 6 x 81 | 0 x 80 |
6 x 512 | 7 x 64 | 6 x 8 | 0 x 0 |
3072 | 448 | 48 | 0 |
3568 |
(iii) 455
Watch this video for more understanding:
6. Express the following decimal numbers into hexadecimal numbers.
(i) 548
16 | 548 | 4 |
16 | 34 | 2 |
2 | ||
Ans.: | 548 | 224 |
(ii) 4052
16 | 4052 | 4 |
16 | 253 | 13-D |
15 | 15-F | |
Ans.: | 548 | FD4 |
(iii) 58
16 | 58 | 10-A |
3 | ||
Ans.: | 58 | 3A |
Watch this video for more understanding:
- Express the following hexadecimal numbers into equivalent decimal numbers.
(II) 9E1A
9 | E | 1 | A |
3 | 2 | 1 | 0 |
9 x 163 | 14 x 162 | 1 x 161 | 10 X 160 |
9 x 4096 | 14 x 256 | 1 X 16 | 10 X 1 |
36864 | 3584 | 16 | 10 |
Ans.: | 40474 |
(iii) 6DB
6 | B | D |
2 | 1 | 0 |
6 x 162 | 11 x 161 | 13 x 160 |
6 X 256 | 11 x 16 | 13 X 1 |
1536 | 176 | 13 |
1725 |
- Convert the following binary numbers into octal and hexadecimal numbers.
Whenever you are going to convert binary to hexadecimal follow the shortcut method.
(i) 1110001000
Octal Number
0 | 0 | 1 | 1 | 1 | 0 | 0 | 0 | 1 | 0 | 0 | 0 |
Z | Y | X | W | ||||||||
1 | 6 | 1 | 0 |
0 | 0 | 0 | 0 | W |
1 | 0 | 0 | 1 | X & Z |
2 | 0 | 1 | 0 | |
3 | 0 | 1 | 1 | |
4 | 1 | 0 | 0 | |
5 | 1 | 0 | 1 | |
6 | 1 | 1 | 0 | Y |
7 | 1 | 1 | 1 |
Hexadecimal Number
0 | 0 | 1 | 1 | 1 | 0 | 0 | 0 | 1 | 0 | 0 | 0 |
Z | Y | X |
0 | 0 | 0 | 0 | 0 | |
1 | 0 | 0 | 0 | 1 | |
2 | 0 | 0 | 1 | 0 | |
3 | 0 | 0 | 1 | 1 | Z |
4 | 0 | 1 | 0 | 0 | |
5 | 0 | 1 | 0 | 1 | |
6 | 0 | 1 | 1 | 0 | |
7 | 0 | 1 | 1 | 1 | |
8 | 1 | 0 | 0 | 0 | X & Y |
9 | 1 | 0 | 0 | 1 | |
10 | 1 | 0 | 1 | 0 | |
11 | 1 | 0 | 1 | 1 | |
12 | 1 | 1 | 0 | 0 | |
13 | 1 | 1 | 0 | 1 | |
14 | 1 | 1 | 1 | 0 | |
15 | 1 | 1 | 1 | 1 |
(ii) 110110101
Octal Number
1 | 1 | 0 | 1 | 1 | 0 | 1 | 0 | 1 |
Z | Y | X |
0 | 0 | 0 | 0 | |
1 | 0 | 0 | 1 | |
2 | 0 | 1 | 0 | |
3 | 0 | 1 | 1 | |
4 | 1 | 0 | 0 | |
5 | 1 | 0 | 1 | X |
6 | 1 | 1 | 0 | Y & Z |
7 | 1 | 1 | 1 |
Ans. : (110110101)2 = (665)8
Hexadecimal Number
1 | 1 | 0 | 1 | 1 | 0 | 1 | 0 | 1 |
Z | Y | X |
0 | 0 | 0 | 0 | 0 | |
1 | 0 | 0 | 0 | 1 | Z |
2 | 0 | 0 | 1 | 0 | |
3 | 0 | 0 | 1 | 1 | |
4 | 0 | 1 | 0 | 0 | |
5 | 0 | 1 | 0 | 1 | X |
6 | 0 | 1 | 1 | 0 | |
7 | 0 | 1 | 1 | 1 | |
8 | 1 | 0 | 0 | 0 | |
9 | 1 | 0 | 0 | 1 | |
10 | 1 | 0 | 1 | 0 | |
11 | 1 | 0 | 1 | 1 | Y |
12 | 1 | 1 | 0 | 0 | |
13 | 1 | 1 | 0 | 1 | |
14 | 1 | 1 | 1 | 0 | |
15 | 1 | 1 | 1 | 1 |
Ans. (110110101)2=(1B5)16
(iii) 1010100
Octal Number
1 | 0 | 1 | 0 | 1 | 0 | 0 |
Z | Y | X |
0 | 0 | 0 | 0 | |
1 | 0 | 0 | 1 | Z |
2 | 0 | 1 | 0 | Y |
3 | 0 | 1 | 1 | |
4 | 1 | 0 | 0 | X |
5 | 1 | 0 | 1 | |
6 | 1 | 1 | 0 | |
7 | 1 | 1 | 1 |
Ans. : (1010100)2=(124)8
Hexadecimal Number
1 | 0 | 1 | 0 | 1 | 0 | 0 |
Y | X |
0 | 0 | 0 | 0 | 0 | |
1 | 0 | 0 | 0 | 1 | |
2 | 0 | 0 | 1 | 0 | |
3 | 0 | 0 | 1 | 1 | |
4 | 0 | 1 | 0 | 0 | X |
5 | 0 | 1 | 0 | 1 | Y |
6 | 0 | 1 | 1 | 0 | |
7 | 0 | 1 | 1 | 1 | |
8 | 1 | 0 | 0 | 0 | |
9 | 1 | 0 | 0 | 1 | |
10 | 1 | 0 | 1 | 0 | |
11 | 1 | 0 | 1 | 1 | |
12 | 1 | 1 | 0 | 0 | |
13 | 1 | 1 | 0 | 1 | |
14 | 1 | 1 | 1 | 0 | |
15 | 1 | 1 | 1 | 1 |
Ans.: (1010100)2=(54)16
(iv) 1010.1001
Octal Number
Integer Part | |||||
1 | 0 | 1 | 0 | ||
Y | X | ||||
Fractional Part | |||||
1 | 0 | 0 | 1 | 0 | 0 |
X | Y |
0 | 0 | 0 | 0 | Integer | Fractional |
1 | 0 | 0 | 1 | Y | |
2 | 0 | 1 | 0 | X | |
3 | 0 | 1 | 1 | ||
4 | 1 | 0 | 0 | X & Y | |
5 | 1 | 0 | 1 | ||
6 | 1 | 1 | 0 | ||
7 | 1 | 1 | 1 |
(1010.1001)2=(12.44)8
Hexadecimal Number
1 | 0 | 1 | 0 |
X | |||
Fractional Part | |||
1 | 0 | 0 | 1 |
X |
0 | 0 | 0 | 0 | 0 | Integer | Fractional |
1 | 0 | 0 | 0 | 1 | ||
2 | 0 | 0 | 1 | 0 | ||
3 | 0 | 0 | 1 | 1 | ||
4 | 0 | 1 | 0 | 0 | ||
5 | 0 | 1 | 0 | 1 | ||
6 | 0 | 1 | 1 | 0 | ||
7 | 0 | 1 | 1 | 1 | ||
8 | 1 | 0 | 0 | 0 | ||
9 | 1 | 0 | 0 | 1 | X | |
10 | 1 | 0 | 1 | 0 | X | |
11 | 1 | 0 | 1 | 1 | ||
12 | 1 | 1 | 0 | 0 | ||
13 | 1 | 1 | 0 | 1 | ||
14 | 1 | 1 | 1 | 0 | ||
15 | 1 | 1 | 1 | 1 |
Ans.: (1010.1001)2=(A.9)16
- Write the binary equivalent of the following octal numbers.
(ii) 5610
0 | 0 | 0 | 0 | Z |
1 | 0 | 0 | 1 | Y |
2 | 0 | 1 | 0 | |
3 | 0 | 1 | 1 | |
4 | 1 | 0 | 0 | |
5 | 1 | 0 | 1 | W |
6 | 1 | 1 | 0 | X |
7 | 1 | 1 | 1 |
(5610)8=(101 110 001 000)2
(iii) 742
0 | 0 | 0 | 0 | |
1 | 0 | 0 | 1 | |
2 | 0 | 1 | 0 | Z |
3 | 0 | 1 | 1 | |
4 | 1 | 0 | 0 | Y |
5 | 1 | 0 | 1 | |
6 | 1 | 1 | 0 | |
7 | 1 | 1 | 1 | X |
(742)8 =(111 100 010)2
(iv) 65.203
0 | 0 | 0 | 0 | Integer | Fractional |
1 | 0 | 0 | 1 | ||
2 | 0 | 1 | 0 | X | |
3 | 0 | 1 | 1 | Z | |
4 | 1 | 0 | 0 | Y | |
5 | 1 | 0 | 1 | Y | |
6 | 1 | 1 | 0 | X | |
7 | 1 | 1 | 1 |
(65.243)8=(110 101. 010 100 011)2
If you are looking for a calculator to check the conversion follow this link: Rapid tables
- Write a binary representation of the following hexadecimal numbers: (i) 4026 (ii) BCA1 (iii) 98E (iv) 132.45 – Do yourself.
- How does computer understand the following text? (hint: 7 bit ASCII code)
(i) HOTS
- ASCII value of H is 72 and its equivalent 7-bit binary code = 1001000
- ASCII value of O is 79 and its equivalent 7-bit binary code = 1001111
- ASCII value of S is 83 and its equivalent 7-bit binary code = 1010011
- ASCII value of T is 84 and its equivalent 7-bit binary code = 1010100
H | O | S | T | |
ASCII Code | 72 | 79 | 83 | 84 |
Binary Value | 1001000 | 1001111 | 1010011 | 1010100 |
(ii) Main
- ASCII value of M is 77 and its equivalent 7-bit binary code = 1001101
- ASCII value of a is 97 and its equivalent 7-bit binary code = 1100001
- ASCII value of i is 105 and its equivalent 7-bit binary code = 1101001
- ASCII value of n is 110 and its equivalent 7-bit binary code = 1101110
M | a | i | n | |
ASCII Code | 77 | 97 | 105 | 110 |
Binary Value | 1001101 | 1100001 | 1101001 | 1101110 |
(iii) CaSe
- ASCII value of C is 67 and its equivalent 7-bit binary code = 1000011
- ASCII value of a is 97 and its equivalent 7-bit binary code = 1100001
- ASCII value of S is 83 and its equivalent 7-bit binary code = 1010011
- ASCII value of e is 101 and its equivalent 7-bit binary code = 1100101
C | a | S | e | |
ASCII Code | 67 | 97 | 83 | 101 |
Binary Value | 1000011 | 1100001 | 1010011 | 1100101 |
- The hexadecimal number system uses 16 literals (0 – 9, A– F). Write down its base value.
- The base value of Binary number is 16.
- Let X be a number system having B symbols only. Write down the base value of this number system.
- A base of the number system is the symbols or digits used in the number system. Hence the base of the X number system is B.
- Write the equivalent hexadecimal and binary values for each character of the phrase given below. – ‘‘ हम सब एक”
- ह – 0939 – 100100111001
- म – 092E – 100100101110
- स – 0938 – 100100111000
- ब – 092C – 100100101100
- ए – 090F – 100100001111
- क – 0915 – 100100010101
- What is the advantage of preparing a digital content in Indian language using UNICODE font?
- It allows to incorporate all the characters of every written language.
- It provides a unique number for every character
- Every character represented thorugh unicode is compatible for various devices like mobile, tables, computer and os like Linux, Windows, Android etc.
- Explore and list the steps required to type in an Indian language using UNICODE.
Step 1: Type the instruction in the Indian language
Step 2: Each character has its own hexadecimal code that the machine will read that code.
Step 3: The machine will then convert that UNICODE to binary code and do the task according to the instruction given
- Encode the word ‘COMPUTER’ using ASCII and convert the encoded value into binary values.
Ans.:
C | 67 | 1000011 |
O | 79 | 1001111 |
M | 77 | 1001101 |
P | 80 | 1010000 |
U | 85 | 1010101 |
T | 84 | 1010100 |
E | 69 | 1000101 |
R | 82 | 1010010 |
Follow this link to read NCERT Solution for Chapter 1 Computer System.
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