Chapter 2 Encoding Scheme and Number System Class 11 NCERT Easy solutions

In this article, I will provide Chapter 2 Encoding Scheme and Number System Class 11 NCERT Solutions. So let’s start1

Chapter 2 Encoding Scheme and Number System Class 11

Let’s start the solution of the encoding scheme and number system class 11 with basic questions.

  1. Write base values of binary, octal and hexadecimal number system.
    • Binary – 2
    • Octal – 8
    • Hexadecimal – 16
  2. Give the full form of ASCII and ISCII.
    • ASCII – Americal Standard Code for Information Interchange
    • ISCII – Indian Script Code for Information Interchange
  3. Try the following conversions:
Chapter 2 Encoding Schemes and Number System Q2 1
Octal to Binary Class 11
Chapter 2 Encoding Scheme and Number System Class 11 NCERT Easy solutions

(IV) (49D)16=(?)10

49D
210
4 x 1629 x 16113 x 160
4 x 2569 x 1613 x 1
102414413
  1181
Binary to decimal class 11

(VI) (1010111)2 = (?)10

1010111
6543210
1 x 260 x 251 x 240 x 231 x 221 x 211 x 20
1 x 640 x 321 x 160 x 81 x 41 x 21 x 1
640160421
      87
  1. Do the following conversions from decimal numbers to other number systems.
Decimal to binary class 11

(ii)

encoding schmes and number system decimal to binary
Chapter 2 Encoding Scheme and Number System Class 11 NCERT Easy solutions

(iv) (889)10 = (?)8

88891
81117
8135
 11
Ans.:8891571
decimal to hexadecimal class 11

(vi) (108)10 =(?)16

1610812-C
 66
 Ans.:1086C

Watch this video for more understanding:

5. Express the following octal numbers into their equivalent decimal numbers.
(i) 145

Encoding Scheme and Number System Octal to decimal

(ii) 6760

6760
3210
6 x 837 x 826 x 810 x 80
6 x 5127 x 646 x 80 x 0
3072448480
   3568

(iii) 455

Chapter 2 Encoding Scheme and Number System Class 11 NCERT Easy solutions

Watch this video for more understanding:

6. Express the following decimal numbers into hexadecimal numbers.
(i) 548

165484
16342
 2 
Ans.:548224

(ii) 4052

1640524
1625313-D
 1515-F
Ans.:548FD4

(iii) 58

165810-A
 3 
Ans.:583A
Chapter 2 Encoding Scheme and Number System Class 11 NCERT Easy solutions

Watch this video for more understanding:

  1. Express the following hexadecimal numbers into equivalent decimal numbers.
Chapter 2 Encoding Scheme and Number System Class 11 NCERT Easy solutions
Chapter 2 Encoding Scheme and Number System Class 11 NCERT Easy solutions

(II) 9E1A

9E1A
3210
9 x 16314 x 1621 x 16110 X 160
9 x 409614 x 2561 X 1610 X 1
3686435841610
   Ans.:40474

(iii) 6DB

6BD
210
6 x 16211 x 16113 x 160
6 X 25611 x 1613 X 1
153617613
  1725
  1. Convert the following binary numbers into octal and hexadecimal numbers.
    Whenever you are going to convert binary to hexadecimal follow the shortcut method.

(i) 1110001000

Octal Number

001110001000
ZYXW
1610
0000W
1001X & Z
2010 
3011 
4100 
5101 
6110Y
7111 

Hexadecimal Number

001110001000
ZYX
00000 
10001 
20010 
30011Z
40100 
50101 
60110 
70111 
81000X & Y
91001 
101010 
111011 
121100 
131101 
141110 
151111 

(ii) 110110101

Octal Number

110110101
ZYX
0000 
1001 
2010 
3011 
4100 
5101X
6110Y & Z
7111 

Ans. : (110110101)2 = (665)8

Hexadecimal Number

110110101
ZYX
00000 
10001Z
20010 
30011 
40100 
50101X
60110 
70111 
81000 
91001 
101010 
111011Y
121100 
131101 
141110 
151111 

Ans. (110110101)2=(1B5)16

(iii) 1010100

Octal Number

1010100
ZYX
0000 
1001Z
2010Y
3011 
4100X
5101 
6110 
7111 

Ans. : (1010100)2=(124)8

Hexadecimal Number

1010100
YX
00000 
10001 
20010 
30011 
40100X
50101Y
60110 
70111 
81000 
91001 
101010 
111011 
121100 
131101 
141110 
151111 

Ans.: (1010100)2=(54)16

(iv) 1010.1001

Octal Number

Integer Part
1010
YX
Fractional Part
100100
XY
0000IntegerFractional
1001Y 
2010X 
3011  
4100 X & Y
5101  
6110  
7111  

(1010.1001)2=(12.44)8

Hexadecimal Number

1010
X
Fractional Part
1001
X
00000IntegerFractional
10001  
20010  
30011  
40100  
50101  
60110  
70111  
81000  
91001 X
101010X 
111011  
121100  
131101  
141110  
151111  

Ans.: (1010.1001)2=(A.9)16

  1. Write the binary equivalent of the following octal numbers.
Chapter 2 Encoding Scheme and Number System Class 11 NCERT Easy solutions

(ii) 5610

0000Z
1001Y
2010 
3011 
4100 
5101W
6110X
7111 

(5610)8=(101 110 001 000)2

(iii) 742

0000 
1001 
2010Z
3011 
4100Y
5101 
6110 
7111X

(742)8 =(111 100 010)2

(iv) 65.203

0000IntegerFractional
1001  
2010 X
3011 Z
4100 Y
5101Y 
6110X 
7111  

(65.243)8=(110 101. 010 100 011)2

If you are looking for a calculator to check the conversion follow this link: Rapid tables

  1. Write a binary representation of the following hexadecimal numbers: (i) 4026 (ii) BCA1 (iii) 98E (iv) 132.45 – Do yourself.
  2. How does computer understand the following text? (hint: 7 bit ASCII code)

(i) HOTS

  • ASCII value of H is 72 and its equivalent 7-bit binary code = 1001000
  • ASCII value of O is 79 and its equivalent 7-bit binary code = 1001111
  • ASCII value of S is 83 and its equivalent 7-bit binary code = 1010011
  • ASCII value of T is 84 and its equivalent 7-bit binary code = 1010100
HOST
ASCII Code72798384
Binary Value1001000100111110100111010100

(ii) Main

  • ASCII value of M is 77 and its equivalent 7-bit binary code = 1001101
  • ASCII value of a is 97 and its equivalent 7-bit binary code = 1100001
  • ASCII value of i is 105 and its equivalent 7-bit binary code = 1101001
  • ASCII value of n is 110 and its equivalent 7-bit binary code = 1101110
Main
ASCII Code7797105110
Binary Value1001101110000111010011101110

(iii) CaSe

  • ASCII value of C is 67 and its equivalent 7-bit binary code = 1000011
  • ASCII value of a is 97 and its equivalent 7-bit binary code = 1100001
  • ASCII value of S is 83 and its equivalent 7-bit binary code = 1010011
  • ASCII value of e is 101 and its equivalent 7-bit binary code = 1100101
CaSe
ASCII Code679783101
Binary Value1000011110000110100111100101
  1. The hexadecimal number system uses 16 literals (0 – 9, A– F). Write down its base value.
    • The base value of Binary number is 16.
  2. Let X be a number system having B symbols only. Write down the base value of this number system.
    • A base of the number system is the symbols or digits used in the number system. Hence the base of the X number system is B.
  3. Write the equivalent hexadecimal and binary values for each character of the phrase given below. – ‘‘ हम सब एक”
  • ह – 0939 – 100100111001
  • म – 092E – 100100101110
  • स – 0938 – 100100111000
  • ब – 092C – 100100101100
  • ए – 090F – 100100001111
  • क – 0915 – 100100010101
  1. What is the advantage of preparing a digital content in Indian language using UNICODE font?
  • It allows to incorporate all the characters of every written language.
  • It provides a unique number for every character
  • Every character represented thorugh unicode is compatible for various devices like mobile, tables, computer and os like Linux, Windows, Android etc.
  1. Explore and list the steps required to type in an Indian language using UNICODE.

Step 1: Type the instruction in the Indian language
Step 2: Each character has its own hexadecimal code that the machine will read that code. 
Step 3: The machine will then convert that UNICODE to binary code and do the task according to the instruction given

  1. Encode the word ‘COMPUTER’ using ASCII and convert the encoded value into binary values.

Ans.:

C671000011
O791001111
M771001101
P801010000
U851010101
T841010100
E691000101
R821010010

Follow this link to read NCERT Solution for Chapter 1 Computer System.

Chapter The Computer System

To read the complete study material of Class 11 Computer Science, follow this link:

Computer Science Class 11

If you are looking for the quiz of computer science class 11, follow this link:

Chapter Wise online tests for Computer Science class 11

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